How do you standardize 0.05 M potassium iodate solution?

Potassium Iodate (0.05M) 

Molecular formula: KIO₃ 

Molecular weight: 214 

Preparation: Weigh accurately 10.7 g of potassium iodate (pure standard) previously dried at 110°C to constant weight, transfer in a volumetric flask, and add sufficient water to produce 1000 mL. 

Standardization: Dilute 25 mL of potassium iodate solution to 100 mL with water. To  25 mL of this solution add 2 g of potassium iodide and 1M H₂SO₄ and titrate with 0.05M  sodium thiosulphate using starch solution as an indicator added towards the endpoint. 

Reaction: 

KIO₃ + 5KI + 3H₂SO₄ → 3I₂ + 3K₂SO₄ + 3H₂O 

3[2Na₂S₂O₃ + I₂ → Na₂S₄O₆ + 2NaI]

Factor calculation: 

Since,

6Na₂S₂O₃ ≅ 3I₂ ≅ potassium iodate (KIO₃) 

6 moles of Na₂S₂O₃ ≅ 1 mole of KIO₃ 

6000 mL of 1M Na₂S₂O₃ ≅ 214 g of KIO₃ 

1 mL of 0.05M Na₂S₂O₃ ≅ 0.00178 g of KIO₃

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