How do you standardize 0.05 M potassium iodate solution?

Potassium Iodate (0.05M) 

Molecular formula: KIO3 

Molecular weight: 214 

Preparation: Weigh accurately 10.7 g of potassium iodate (pure standard) previously dried at 110°C to constant weight, transfer in a volumetric flask, and add sufficient water to produce 1000 mL. 

Standardization: Dilute 25 mL of potassium iodate solution to 100 mL with water. To  25 mL of this solution add 2 g of potassium iodide and 1M H2SO4 and titrate with 0.05M  sodium thiosulphate using starch solution as an indicator added towards the endpoint. 


KIO3 + 5KI + 3H2SO4 → 3I2 + 3K2SO4 + 3H2

3[2Na2S2O3 + I2 → Na2S4O6 + 2NaI]

Factor calculation: 


6Na2S2O3 ≅ 3I2 ≅ potassium iodate (KIO3

6 moles of Na2S2O3 ≅ 1 mole of KIO3 

6000 mL of 1M Na2S2O3 ≅ 214 g of KIO3 

1 mL of 0.05M Na2S2O3 ≅ 0.00178 g of KIO3

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