# Solubility of Gas in Liquids

Solubility of gas in liquids is the concentration of dissolved gas in the liquid when it is in equilibrium with the pure gas above the solution. The example of gas in a liquid includes effervescent preparations containing dissolved carbon dioxide, ammonia water, and hydrochloride gas. Aerosol products containing nitrogen or carbon dioxide as propellant are also considered to be the solution of gases in liquids.

#### Factors Affecting Solubility of Gas in Liquids:

The solubility of gas in liquids depends on pressure, temperature, salt present, chemical reaction, and micellar solubilization.

#### Pressure:

Liquids and solids exhibit practically no change of solubility with changes in pressure. When considering the solubility of gases in liquids, the pressure of the gas in contact with the liquid is important. At higher gas pressure, more gas is dissolved in liquids, Fig 1.6. For example, the soda bottle is packed at high pressure of carbon dioxide before sealing. When the cap of the bottle is opened, the pressure above the liquid is reduced to 1 atm, and the soda fizzes. This fizzing is just carbon dioxide that was dissolved in soda, is getting released. Therefore, if lower is the pressure less carbon dioxide is soluble.

The effect of pressure on the solubility of gas is given Henry’s law which states that in dilute solution the mass of gas that dissolves in each volume of liquid solvent at constant temperature is directly proportional to the partial pressure of the gas. Mathematically it is expressed as

Sg = KH Pg

Where Sg is the solubility of gas, expressed as mol/L; KH is Henry law constant which is different for each solute-solvent system and Pg is the partial pressure of the gas in mmHg. The amount of undissolved gas above the solution is obtained by subtracting the vapor pressure of the pure liquid from the total pressure of the solution.

Example: The solubility of pure gas in water at 25 °C and 1 atm pressure is 1.5 × 10-3 mol/L. What will be the concentration of the gas at the same temperature at 0.5 atm?

Solution: Given that: Pressure = 1 atm = 101.3 kPa

Concentration = 1.5 × 10-3 mol/L

Solubility (Sg) = ?

Sg = KH Pg

1.5 × 10-3 = KH × 101.3

KH = 1.519 × 10-5

Now, at P = 0.5 atm = 0.5 × 101.3 kPa

Sg = KHPg

= 1.519 × 10-5 × 0.5 × 101.3

= 7.693 × 10-4 mole/L

The concentration of gas at 25°C and 0.5 atm pressure will be 7.693 × 10-4 mole/L.

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